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In Figure, \(X\) and \(Y\) are respectively the mid-points of the opposite sides \(AD\) and \(BC\) of a parallelogram \(ABCD\). Also, \(BX\) and \(DY\) intersect \(AC\) at \(P\) and \(Q\), respectively. Show that \(AP = PQ = QC\).
![YCIND_240307_6088_quadrilateral_2.png](https://resources.cdn.yaclass.in/04ffc610-95ae-4b59-9305-3ada8c5bea79/YCIND2403076088quadrilateral2w300.png)
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