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In a triangle \(ABC\) right angled at \(A\), a perpendicular of length 16 units from \(A\) meets the side \(BC\) at \(D\) at a distance of 18 units from \(C\). If \(AB\) \(=\) 20 units, find the area of the triangle \(ABC\).
 
Answer:
 
The area of the triangle \(ABC\) \(=\) 
 square units.