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Calculate the number of water molecules present in one drop of water that weighs \(0.18\) \(g\).
Given data:
Mass of one drop of water \(=\) \(0.18\) \(g\)
Molecular mass of water \(=\)
Solution:
\(\text{No. of moles}\) \(=\)
Where,
X is
Y is
\(=\) \(mole\)
\(\text{No. of molecules}\) \(=\)\(\ (\text {x} )\ \cdot\ (\text {y} )\)
Where,
x is
y is
\(=\) \(6.023\times10^{z}\) \(molecules\)
z is
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