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Mark a point \(A\), where the perpendicular bisector intersects the ray \(BX\). Then, join \(AC\).

Draw a line segment \(BC = 8 \ cm\).

Draw a perpendicular bisector \(EF\) of line segment \(CD\).

The line \(BX\) extended to opposite side of the line segment \(BC\). With \(B\) as the centre and \(2.5 \ cm\) as radius, draw an arc that cuts the extended \(BX\) at \(D\). Then, join \(CD\).

Make \(\angle XBC = 60^\circ\).

Construct a triangle \(ABC\) in which \(BC = 8 \ cm\), \(\angle B = 60^\circ\) and \(AC - AB = 60 \ cm\).

**Step 1**:

**Step 2**:

**Step 3**:

**Step 4**:

**Step 5**:

**Thus**, \(ABC\)

**is the required triangle**.