UPSKILL MATH PLUS

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Learn more### Theory:

Let us consider the equation \(3y-2=1\). Now, let us graph the equation.

First, let us simplify the equation by keeping the variable in the LHS and the constant in the RHS.

Thus, we have:

\(3y-2=1\)

\(3y-2+2=1+2\) (Add \(2\) on both sides of the equation)

\(3y=3\)

\(\frac{3y}{3}=\frac{3}{3}\) (Divide both sides of the equation by \(3\))

\(y=1\)

Therefore, the simplified equation is \(y=1\). To plot the graph, we need \(x\) value also. From the equation, we can see that whatever is the value of \(x\), \(y\) is \(1\).

Some of the ordered pairs are \((-2,1)\), \((-1,1)\), \((0,1)\), \((1,1)\), \((2,1)\), \((3,1)\)

Now, let us plot these ordered pairs in the graph and join them.

Here, the scale is \(x\)-axis \(1 \ cm=1 \ unit\) and \(y\)-axis \(1 \ cm = 1 \ unit\).

This is the graph of the linear equation \(3y-2=1\).