\(ΔABC\) is an isosceles with \(AB = AC =\) 11 \(cm\) and \(BC =\) 12 \(cm\). The height \(AD\) from \(A\) to \(BC\) is 6 \(cm\). Find the area of \(ΔABC\) and the height from \(C\) to \(AB\), i.e., \(CE\).
The area of \(ΔABC\) is \(cm²\).
The height of the \(CE\) is \(cm\).