LEARNATHON

III

Competition for grade 6 to 10 students! Learn, solve tests and earn prizes!

Learn more### Theory:

We know that,

- Protons and neutrons are found in the nucleus of atoms.
- Neutrons have no charge, whereas protons have a positive charge.
- The magnitudes of positive and negative charges in an atom are equal, resulting in an electrically neutral atom.

*Structure of an atom*

The number of protons in the nucleus of an atom is known as its atomic number.

The symbol "Z" stands for the atomic number. Atom of different element has a different number of protons.

The symbol "Z" stands for the atomic number. Atom of different element has a different number of protons.

The number of electrons and number of protons is equal in a neutral atom.

**Example:**

The atomic number of carbon is \(6\); hence, the number of protons in the nucleus is \(6\). Similarly, atomic number of nitrogen is \(7\); hence, the number of protons in the nucleus is \(7\).

We can easily calculate the number of electrons or protons in an atom if we know its atomic number. Let us recall the points for that.

- The atomic number is the number of protons.
- In a neutral atom, the number of protons are equal to the number of electrons.

**Example:**For \(O\), calculate the number of (i) protons and (ii) electrons.

Atomic number of oxygen = 8.

(i) Protons

We know, the atomic number is equal to the number of protons.

Hence, the number of protons = \(8\)

(ii) Electrons

In a neutral atom, the number of protons are equal to the number of electrons.

Hence, the number of electrons = \(8\)

Mass Number

We have studied that the mass of an atom is concentrated in its nucleus because the size of the electron is negligible.

A mass number or atomic mass of an atom is equal to the sum of the number of protons and neutrons present in the nucleus. Hence, the protons and neutrons are also called nucleons.

$\mathit{Mass}\phantom{\rule{0.147em}{0ex}}\mathit{number}=\mathit{Number}\phantom{\rule{0.147em}{0ex}}\mathit{of}\phantom{\rule{0.147em}{0ex}}\mathit{protons}+\mathit{Number}\phantom{\rule{0.147em}{0ex}}\mathit{of}\phantom{\rule{0.147em}{0ex}}\mathit{neutrons}$ (or) $\mathit{Mass}\phantom{\rule{0.147em}{0ex}}\mathit{number}=\mathit{Atomic}\phantom{\rule{0.147em}{0ex}}\mathit{number}+\mathit{Number}\phantom{\rule{0.147em}{0ex}}\mathit{of}\phantom{\rule{0.147em}{0ex}}\mathit{neutrons}$

The mass number or atomic mass is represented by the symbol "A".

By rearranging the atomic mass formula, we can calculate the number of protons, or neutrons, or atomic number.

$\mathit{Number}\phantom{\rule{0.147em}{0ex}}\mathit{of}\phantom{\rule{0.147em}{0ex}}\mathit{neutrons}=\mathit{Mass}\phantom{\rule{0.147em}{0ex}}\mathit{number}-\mathit{Number}\phantom{\rule{0.147em}{0ex}}\mathit{of}\phantom{\rule{0.147em}{0ex}}\mathit{protons}$ (or) $\mathit{Number}\phantom{\rule{0.147em}{0ex}}\mathit{of}\phantom{\rule{0.147em}{0ex}}\mathit{neutrons}=\mathit{Mass}\phantom{\rule{0.147em}{0ex}}\mathit{number}-\mathit{Atomic}\phantom{\rule{0.147em}{0ex}}\mathit{number}$

$\mathit{Number}\phantom{\rule{0.147em}{0ex}}\mathit{of}\phantom{\rule{0.147em}{0ex}}\mathit{protons}=\mathit{Mass}\phantom{\rule{0.147em}{0ex}}\mathit{number}-\mathit{Number}\phantom{\rule{0.147em}{0ex}}\mathit{of}\phantom{\rule{0.147em}{0ex}}\mathit{neutrons}$ (or) $\mathit{Atomic}\phantom{\rule{0.147em}{0ex}}\mathit{number}=\mathit{Mass}\phantom{\rule{0.147em}{0ex}}\mathit{number}-\mathit{Number}\phantom{\rule{0.147em}{0ex}}\mathit{of}\phantom{\rule{0.147em}{0ex}}\mathit{neutrons}$

**Example:**Carbon

Number of protons = \(6\)

Number of neutrons = \(6\)

Hence, the mass number = \(6\) + \(6\) = \(12 u\)

The atomic number (Z), mass number (A) and symbol of an element are written as follows in atomic notation:

${}_{Z}{}^{A}X$

Where, X is the symbol of element.

A = Protons + Neutrons

Z = Protons or electrons