Exercise Problem V — task. Mathematics CBSE, Class 10.

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In Fig., if \(TP\) and \(TQ\) are the two tangents to a circle with centre \(O\) so that \(\angle POQ = 110^°\), then \(\angle PTQ\) is equal to

\(60^o\)
\(90^o\)
\(70^o\)
\(80^o\)

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