Exemplar exercise problems II — task. Mathematics CBSE, Class 10.

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1. Given that \(sin \ \theta = \frac{a}{b}\), then \(cos \ \theta\) is equal to

\(\frac{b}{\sqrt{b^2 - a^2}}\)
\(\frac{b}{a}\)
\(\frac{\sqrt{b^2 - a^2}}{b}\)
\(\frac{a}{\sqrt{b^2 - a^2}}\)

2. If \(\triangle ABC\) is right-angled at \(C\), then the value of \(cos \ (A + B)\) is

\(0\)
\(1\)
\(\frac{1}{2}\)
\(\frac{\sqrt{3}}{2}\)

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