Express in terms of the ratio 'sin' — task. Mathematics CBSE, Class 10.

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Express \(\tan θ\) in terms of \(\sin θ\).

\(\frac{\sin θ}{\sqrt{1 - \sin^2 θ}}\)
\(\frac{\sqrt{1 - \sin^2 θ}}{\sin θ}\)
\(\frac{\sqrt{1 + \sin^2 θ}}{\sin θ}\)
\(\frac{\sin θ}{\sqrt{1 + \sin^2 θ}}\)

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