Prove the given trigonometric equation — task. Mathematics CBSE, Class 10.

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Answer variants:

\frac{\sin θ (1 - \cos θ)}{(1 + \cos θ) (1 - \cos θ)}

\frac{\sin θ (1 - \cos θ)}{\sin^{2} θ}

\frac{\sin θ (1 - \cos θ)}{1 - \cos^{2} θ}

\frac{\sin θ}{1 + \cos θ} \times \frac{1 + \cos θ}{1 + \cos θ}

\frac{\sin θ (1 + \cos θ)}{1 - \cos^{2} θ}

\frac{\sin θ}{1 + \cos θ} \times \frac{1 - \cos θ}{1 - \cos θ}

Prove that

\frac{\sin θ}{1 + \cos θ}

\(=\)

\frac{1 - \cos θ}{\sin θ}

Proof:

LHS \(=\)

\frac{\sin θ}{1 + \cos θ}

\(=\)

\frac{1 - \cos θ}{\sin θ}

\(=\) RHS

Did you find an error?

7. Prove the given trigonometric equation