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Answer variants:
\(0^{\circ}\)
\(90^{\circ}\)
The triangle \(PQR\) is right-angled at \(Q\). If \(PQ\) \(=\) \(cm\) and \(PR\) \(=\) \(cm\), then find \(\angle QRP\).
Answer:
The measure of \(\angle QRP\) \(=\)
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