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Find the zeroes of the polynomial \(v^2 + 4 \sqrt{3} v - 15\), and verify the relation between the coefficients and the zeroes of the polynomial.
 
Answer:
 
The zeroes are
and
.
 
Sum of the zeroes \(=\)
 
Product of the zeroes \(=\)
Answer variants:
−coefficientofvcoefficientofv2=43
−coefficientofvcoefficientofv2=−43
\(v = -\sqrt{3}\)
\(v = 5 \sqrt{3}\)
\(v = \sqrt{3}\)
\(v = -5 \sqrt{3}\)
−constantcoefficientofv2=−15
constantcoefficientofv2=−15