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Find whether the equation \(-2x^2 + 3x + 2 = 0\) has real roots. If real roots exist, find them.
 
Answer:
 
\(-2x^2 + 3x + 2 = 0\) has
.
 
The roots are
and
.
Answer variants:
two distinct real roots
\(\frac{-1}{2}\)
no real roots
two equal real roots
\(-2\)
\(\frac{1}{2}\)
\(2\)