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Answer variants:
\(6 + \sqrt{31} = \frac{p}{q}\)
satisfies
co-primes
\(\frac{6q + p}{q}\) is rational
cannot be expressed as p/q form
composites
can be expressed as p/q form
contradicts
irrational Number
\(\frac{6q + p}{q} = \sqrt{31}\)
rational Number
Let's prove 6+31 is an irrational number.
 
Now prove by contradiction method.
 
1. Assume 6+31 is a
2. By the definition,
3. And \(p\) and \(q\) are
4. So we can write it as
5. Simplifying the term,
6. This implies that,
7. This
 our assumption.
8. Thus, 6+31 is