Determine the value of the variable — task. Mathematics CBSE, Class 10.

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In a \(\triangle ABC\), \(DE \parallel BC\). If \(AD = 3y - 4\), \(DB = 3y - 1\), \(AE = 7y - 6\) and \(EC = 4y - 2\), then find the value of \(y\).

The value of \(y\) is

$\frac{1}{3}$
\(0\)
$\frac{2}{3}$
$- \frac{1}{3}$

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