Theory:

On Monday, Anand purchased \(8\) chocolates each for \(₹10\). On Tuesday, he purchased \(3\) chocolates each for \(₹10\) again. How much he spent in both the days for chocolates.
 
This can be done in two ways:
  1. Monday spent \(+\) Tuesday spent \(=\) 8×10+3×10=80+30=110.
  2. Total number of chocolates he purchased in both the days \(×\) Amount spent for each chocolate \(=\) 8+3×10=11×10=110.
There are some confusions in the calculation. Which operation has to be done first?
 
Whether we have to multiply \(3\) by \(10\) first and then add with \(8\) or we have to add \(8\) and \(3\) and multiply by \(10\)?
 
To get a clear view in order of operation, we have to insert brackets.
First, reduce the number which is present inside the bracket \(( )\) into a single number and then do the operation outside.