### Theory:

On Monday, Anand purchased $$8$$ chocolates each for $$₹10$$. On Tuesday, he purchased $$3$$ chocolates each for $$₹10$$ again. How much he spent in both the days for chocolates.

This can be done in two ways:
1. Monday spent $$+$$ Tuesday spent $$=$$ $8×10\phantom{\rule{0.147em}{0ex}}+\phantom{\rule{0.147em}{0ex}}3×10\phantom{\rule{0.147em}{0ex}}=80+30=110$.
2. Total number of chocolates he purchased in both the days $$×$$ Amount spent for each chocolate $$=$$ $8+3\phantom{\rule{0.147em}{0ex}}×10\phantom{\rule{0.147em}{0ex}}=11×10=110$.
There are some confusions in the calculation. Which operation has to be done first?

Whether we have to multiply $$3$$ by $$10$$ first and then add with $$8$$ or we have to add $$8$$ and $$3$$ and multiply by $$10$$?

To get a clear view in order of operation, we have to insert brackets.
First, reduce the number which is present inside the bracket $$( )$$ into a single number and then do the operation outside.