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Construct a triangle \(PQR\) whose side length is \(14 \ cm\).
Construction:
Step 1:
Step 2:
Step 3:
Step 4:
Thus, \(PQR\) is the required triangle.
Answer variants:
With \(Q\) as centre, draw an arc of radius \(14 \ cm\).
Construct the base \(QR = 14 \ cm\).
Join \(PQ\) and \(QR\).
With \(R\) as centre, draw an arc of radius \(14 \ cm\) which cuts the previous arc at \(P\).
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