UPSKILL MATH PLUS
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Learn moreFind the third angle of a triangle (using a parallel line) when two of the angles are \(39°\) and \(76°\).
Answer:
Let \(ABC\) be the given triangle, where \(\angle B = 76°\) and \(\angle C = 39°\).
Suppose we construct a line \(XY\) parallel to \(BC\) through vertex \(A\).
\(\angle BAX =\) \(°\) [Since ]
\(\angle CAY =\) \(°\) [Since ]
\(\angle BAC =\) \(°\) [By ]
Therefore, the third angle of the triangle \(ABC\) is \(°\).
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