Product of sum and difference (integers) — task. Mathematics CBSE, Class 7.

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Do the multiplication:

({6 a}^{5} - 5 b^{2}) \cdot ({6 a}^{5} + 5 b^{2})

Choose the correct answer:

${6 a}^{10} - {5 b}^{4}$
${36 a}^{10} + {60 a^{5} b^{2} + 25 b}^{4}$
${36 a}^{10} - {25 b}^{4}$
${36 a}^{10} - {60 a^{5} b^{2} - 25 b}^{4}$
${36 a}^{10} - {60 a^{5} b^{2} + 25 b}^{4}$
${36 a}^{7} - {25 b}^{2}$

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