### Exercise condition:

5
$$ΔABC$$ is an isosceles with $$AB = AC =$$ 11 $$cm$$ and $$BC =$$ 10 $$cm$$. The height $$AD$$ from $$A$$ to $$BC$$ is 8 $$cm$$. Find the area of $$ΔABC$$ and the height from $$C$$ to $$AB$$, i.e., $$CE$$.

The area of $$ΔABC$$ is  $$cm²$$.

The height of the $$CE$$ is  $$cm$$.