UPSKILL MATH PLUS

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26. NCERT | Square of Difference of two numbers | Intext | Pg.147 | Q3

Use the identity \((a-b)^2\) to find the values of \(47^2\).

Answer:

We can rewrite \(47^2\) as

{(i - 3)}^{i}

By the identity,

{(a - b)}^{2} = i^{i} - i i i + i^{i}

Thus, \(47^2\) \(=\) .

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