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Find the \(10^{\text{th}}\) and \(n^{\text{th}}\) terms of the \(G.P\): \(6, 12, 24, \ldots\)
 
\(10^{\text{th}}\) term is  
 
 \(n^{\text{th}}\) term is
Answer variants:
3062
\(t_n=3\left(2\right)^{n-1}\)
3132
3102
\(t_n=6(2)^{n+1}\)
\(t_n=3\left(2\right)^{n}\)
\(t_n=6(2)^{n}\)
3072