TBQ - Prove the equality — task. Mathematics CBSE, Class 9 New.

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Prove that the following rational numbers are equal:

(i) \(-\frac{3}{7}\) and \(-\frac{18}{42}\)

(ii) \(\frac{42}{7}\) and \(6\)

Solution:

Any two rational numbers \(\frac{a}{b}\) and \(\frac{c}{d}\) are said to be equal if

i \times i = i \times i

[Note: Enter the answer in alphabetical order.]

Proof:

(i) \(-\frac{3}{7}\) and \(-\frac{18}{42}\)

\(-3 \times 42\) \(=\) ......(1)

\(7 \times (-18)\) \(=\) ......(2)

Equation (1) Equation (2)

Therefore, \(-\frac{3}{7}\) and \(-\frac{18}{42}\) are .

(ii) \(\frac{42}{7}\) and \(6\)

Proof:

\(\frac{42}{7}\) \(=\) \(\frac{6}{1}\)

\(42 \times 1\) \(=\) ......(1)

\(7 \times 6\) \(=\) ......(2)

Equation (1) Equation (2)

Therefore, \(\frac{42}{7}\) and \(6\) are .

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5. TBQ - Prove the equality