Exemplar Exercise Problems V — task. Mathematics CBSE, Class 9.

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1. The area of an isosceles triangle having base \(2 cm\) and the length of one of the equal sides \(4 cm\), is

\(2 \sqrt{15} cm^2\)
\(\sqrt{15} cm^2\)
\(4 \sqrt{15} cm^2\)
\(\sqrt{\frac{15}{2}} cm^2\)

2. The edges of a triangular board are \(6 cm\), \(8 cm\) and \(10 cm\). The cost of painting it at the rate of \(9\) paise per \(cm^2\) is

\(Rs 3.00\)
\(Rs 2.16\)
\(Rs 2.00\)
\(Rs 2.16\)

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