PUMPA - SMART LEARNING
எங்கள் ஆசிரியர்களுடன் 1-ஆன்-1 ஆலோசனை நேரத்தைப் பெறுங்கள். டாப்பர் ஆவதற்கு நாங்கள் பயிற்சி அளிப்போம்
Book Free Demo\(l|| m\) and \(M\) is the mid-point of a line segment \(AB\). Show that \(M\) is also the mid-point of any line segment \(CD\), having its end points on \(l\) and \(m\), respectively.
Proof:
Consider \(\Delta AMC\) and \(\Delta BMD\),
\(\angle BAC = \angle\) ()
\(AM = \) ()
\(\angle AMC = \angle \) ()
Thus, \(\Delta AMC \cong \Delta BMD\) (by congruence rule).
By CPCT, \(MC = \)
Hence, \(M\) is the midpoint of \(CD\).
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