Fill up the blanks — task. Mathematics CBSE, Class 9.

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எங்கள் ஆசிரியர்களுடன் 1-ஆன்-1 ஆலோசனை நேரத்தைப் பெறுங்கள். டாப்பர் ஆவதற்கு நாங்கள் பயிற்சி அளிப்போம்

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Answer variants:

\(CY\) is perpendicular to \(AB\)

CPCT

altitudes

perpendicular line segment

two

\(\triangle ACY\)

\(\angle AXB = \angle AYC\)

\(BX\)

\(ACY\)

Prove that the altitudes are \(BX\) and \(CY\) are equal if triangle \(ABC\) is isosceles with \(AB = AC\).

Proof:

It is given that \(BX\) and \(CY\) are

of triangle \(ABC\).

An altitude is a

An altitude is a perpendicular line segment drawn through the vertex of the triangle to the opposite side.

Here, \(CY\) is an altitude of \(AB\), and

is an altitude of \(AC\).

Hence,

and \(BX\) is perpendicular to \(AC\).

To prove that the altitudes are equal, let us consider

and \(\triangle ABX\).

Here, \(AB = AC\) [Given]

Also,

as the altitudes meet the sides at right angles.

Also, \(\angle A\) is common to both triangles

and \(ABX\).

Here,

corresponding pairs of angles and one corresponding pair of sides are equal.

Thus by congruence criterion, \(\triangle ACY \cong \triangle ABX\).

Since \(\triangle ACY \cong \triangle ABX\), and by

the altitudes \(CY\) and \(BX\) are equal.

Did you find an error?

7. Fill up the blanks