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*Working rule to construct a parallelogram*Let us discuss the working rule to construct a parallelogram when the measure of two adjacent sides and an angle of a parallelogram are given.

Example:

Construct a parallelogram \(ABCD\) with \(AB\) \(=\) \(6\) \(cm\), \(BC\) \(=\) \(5.5\) \(cm\) and \(\angle ABC\) \(=\) \(75^{\circ}\).

Construction:

*: Draw a line segment \(AB\) \(=\) \(6\) \(cm\).*

**Step 1***: With \(B\) as centre, mark an angle \(75^{\circ}\) using the protractor and mark it as \(X\). Join \(BX\).*

**Step 2***: With \(B\) as centre, draw an arc of radius \(5.5\) \(cm\) intersecting \(BX\) at \(C\).*

**Step 3***: With \(C\) and \(A\) as centres, draw two arcs of radii \(6\) \(cm\) and \(5.5\) \(cm\) respectively such that they intersect each other at \(D\).*

**Step 4***: Join \(CD\) and \(AD\).*

**Step 5***: \(ABCD\) is the required parallelogram. The measure of \(CE\) gives the height of the parallelogram \(ABCD\).*

**Step 6**