UPSKILL MATH PLUS
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In the figure, \(O\) is the centre of a circle and diameter \(AB\) bisects the chord \(CD\) at a point \(E\) such that \(CE = ED = 8 \ cm\) and \(EB = 4 \ cm\). The radius of the circle is:
2. In the figure, \(PQRS\) and \(PTVS\) are two cyclic quadrilaterals. If \(\angle QRS = 100^\circ\), then \(\angle TVS = \)
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