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A deck of playing cards will have \(52\) cards altogether.

We can sort the \(52\) cards into the four suits, namely, hearts, clubs, diamonds and spades.

Each suit will comprise of \(13\) cards.

\(13\) cards in Spades \(+\) \(13\) cards in Clubs \(+\) \(13\) cards in Hearts \(+\) \(13\) cards in Diamond \(=\) \(52\) cards

Let us look at a set of diamond cards.

**Imagine**

**all**\(13\) cards

**faced down and shuffled together**.

**What do you think the probability would be that we pick**\(5\) of diamonds

**on the first attempt**?

There are \(13\) cards altogether and there is only one card to be picked.

So, the probability of \(5\) of diamonds being picked at random \(=\) \(\frac{1}{13}\)

Die

Die is a common plaything. It has \(6\) faces, and there are numbers from \(1\) to \(6\) engraved on each of the faces.

**What do you think the possible outcomes be if a die is rolled once**?

The possible outcomes include \(\{\)\(1\), \(2\), \(3\), \(4\), \(5\), \(6\)\(\}\).

**What is the probability that the die lands on**\(6\)

**on the first attempt**?

There are \(6\) possible outcomes, and there is only \(1\) favourable outcome.

Therefore, the probability of getting a \(6\) on the first attempt \(=\) \(\frac{1}{6}\)