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Answer variants:
If \(U\) \(=\) , \(S\) \(=\) and \(T\) \(=\), then prove that \((S \cap T)^{\prime} = S^{\prime} \cup T^{\prime}\).
\(S \cap T\) \(=\) , \((S \cap T)^{\prime}\) \(=\)
\(S^{\prime}\) \(=\) , \(T^{\prime}\) \(=\)
\(S^{\prime} \cup T^{\prime}\) \(=\)
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