UPSKILL MATH PLUS

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If \(A = \{-2, 0, 1, 3, 5\}\), \(B = \{-1, 0, 2, 5, 6\}\) and \(C = \{-1, 2, 5, 6, 7\}\), show that \(A - (B \cup C) = (A - B) \cap (A - C)\).
 
Proof:
 
\(B \cup C =\) i,i,i,i,i,i
 
\(A - (B \cup C) =\) i,i,i ---- (\(1\))
 
\(A - B =\) i,i,i
 
\(A - C =\) i,i,i,i
 
\((A - B) \cap (A - C) =\) i,i,i ---- (\(2\))
 
From equations (\(1\)) and (\(2\)), \(A - (B \cup C) = (A - B) \cap (A - C)\).
 
Hence, we proved.
 
(Note: Enter the numbers in ascending order.)