PUMPA - SMART LEARNING

எங்கள் ஆசிரியர்களுடன் 1-ஆன்-1 ஆலோசனை நேரத்தைப் பெறுங்கள். டாப்பர் ஆவதற்கு நாங்கள் பயிற்சி அளிப்போம்

Book Free Demo
1. Set up a circuit as shown in the below figure, consisting of a nichrome wire \(XY\) of length, say \(0.5\ m\), an ammeter, a voltmeter and four cells of \(1.5\ V\) each. (Nichrome is an alloy of nickel, chromium, manganese, and iron metals.)
 
12.2.png
Circuit diagram
  
2. First use only one cell as the source in the circuit. Note the reading in the ammeter \(I\), for the current and reading of the voltmeter \(V\) for the potential difference across the nichrome wire \(XY\) in the circuit. Tabulate them in the table given.
 
3. Next connect two cells in the circuit and note the respective readings of the ammeter and voltmeter for the values of current through the nichrome wire and potential difference across the nichrome wire.
 
4. Repeat the above steps using three cells and then four cells in the circuit separately.
  
Number of cells used in the circuit
Current through the nichrome wire, (\(I\))
Potential difference across the nichrome wire (\(V\))
\(\frac {V}{I}\)
(\(V/A\))
\(1\)
 
 
 
\(2\)
 
 
 
\(3\)
 
 
 
\(4\)
     
 
5. Calculate the ratio of \(V\) to \(I\) for each pair of potential difference \(V\) and current \(I\).
 
6. Plot a graph between \(V\) and \(I\), and observe the nature of the graph.
 
It is observed that \(\frac {V}{I}\) is  in each case. Also, the \(V-I\) graph shows .