Intext example VI — task. Science CBSE, Class 10.

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A 4

Ω

resistance wire is doubled on it. Calculate the new resistance of the wire.

[Note: Enter the answer as a whole number].

When a wire is doubled on it, its length would become and area of cross-section would . Hence,

Length, \(l\) \(=\)

Area of cross-section, \(A\) \(=\)

The formula to find the resistance is

\begin{array}{l} ρ = \frac{i i}{i} \\ i = \frac{ρ i}{i} \end{array}

The value of resistance is given as

i_{1} = \frac{ρ (\frac{i}{2})}{2 \times i}

On simplifying the values, we get

\frac{R_{1}}{R} = \frac{i}{i}

The value of \(R_1\) \(=\)

Ω

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25. Intext example VI