NCERT Exemplar IV — task. Science CBSE, Class 10.

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A current of \(1\ A\) is drawn by a filament of an electric bulb. Number of electrons passing through a cross section of the filament in \(16\ seconds\) would be roughly

\(10^{18}\)
\(10^{20}\)
\(10^{23}\)
\(10^{16}\)

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63. NCERT Exemplar IV

Exercise condition: