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Subjects
Science CBSE
Class 10
Light reflection and refraction
Textbook questions

11. Exercises XI

Exercise condition:

5 m.

An object \(5\ cm\) is placed at a distance of \(20\ cm\) in front of a convex mirror of radius of curvature \(30\ cm\). Find the position, nature and size of the image.

Formula to focal length of the mirror is,

\(f\ =\ 4R\)
\(f\ =\ \frac{R}{2}\)
\(f\ =\ 2R\)
\(f\ =\ \frac{R}{4}\)

Mirror formula is,

\(\frac{1}{v}\ =\ \frac{1}{f}\ +\ \frac{1}{u}\)
\(\frac{1}{u}\ =\ \frac{1}{v}\ +\ \frac{1}{f}\)
\(\frac{1}{v}\ -\ \frac{1}{u}\ =\ \frac{1}{f}\)
\(\frac{1}{v}\ +\ \frac{1}{u}\ =\ \frac{1}{f}\)

Magnification is,

\(M\ =\ \frac{v}{u}\)
\(M\ =\ \frac{u}{v}\)
\(M\ =\ \frac{-u}{v}\)
\(M\ =\ \frac{-v}{u}\)

Focal length (\(f\)) \(=\) \(cm\)

Image distance (\(v\)) \(=\) \(cm\)

Magnification (\(M\)) \(=\)

Height of the image (\(h_i\)) \(=\) \(cm\)

Nature of the image is,

real, inverted and diminished size
virtual, erect and same size
real, inverted, and same size
virtual, erect and diminished size

Important!

Note: Enter your answers with two decimal digits.

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