PDF chapter test TRY NOW
Write brief answers to the following question:
In photosynthesis, 6 molecules of carbon dioxide combine with an equal number of water molecules through a complex series of reactions to give a molecule of glucose having a molecular formula \(C_6H_1{_2}O_6\). How many grams of water would be required to produce 18 g of glucose? Compute the volume of water so consumed assuming the density of water to be 1 g cm–3.
\(6CO_2 + 6H_2O \xrightarrow[Sunlight]{Chlorophyl} C_6H_1{_2}O_6 + 6O_2\).
1 mole of glucose needs moles of water.
of glucose needs (6×) g of water.
1 g of glucose will need 108 / 180 g of water.
18 g of glucose would need 108 / 180 × 18 g of water = g.
Volume of water used = Mass / Density = 10.8 g / 1 g \(cm^-{^3}\).
= \(cm^3\).
Register for free to see more content