PUMPA - SMART LEARNING
எங்கள் ஆசிரியர்களுடன் 1-ஆன்-1 ஆலோசனை நேரத்தைப் பெறுங்கள். டாப்பர் ஆவதற்கு நாங்கள் பயிற்சி அளிப்போம்
Book Free DemoWrite brief answers to the following question:
A silver ornament of mass ‘m’ gram is polished with gold equivalent to 1% of the mass of silver. Compute the ratio of the number of atoms of gold and silver in the ornament.
Mass of silver = m g.
Mass of gold = m / 100 g.
Number of atoms of silver = Mass / Atomic mass x \(N_A\),
= m / x \(N_A\).
Number of atoms of gold = m / 100 x x \(N_A\).
Ratio of number of atoms of gold to silver = Au : Ag.
= m / x 197 x \(N_A\) : m / 108 x \(N_A\).
= 108 : 100 × 197.
= .
= .
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