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Using a horizontal force of 200 N, we intend to move a wooden cabinet across a floor at a constant velocity. What is the friction force that will be exerted on the cabinet?
Since the velocity of the cabinet is constant, its acceleration must be . Therefore, the effective force acting on the cabinet is also .
This suggests that the magnitude of opposing frictional force is to the force exerted on the cabinet, which is 200 N. Therefore, the total friction force is .
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