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A stone is thrown in a vertically upward direction with a velocity of \(5\ m\ s^{-1}\). If the acceleration of the stone during its motion is \(10\ m\ s^{–2}\) in the downward direction, what will be the height attained by the stone and how much time will it take to reach there?
From the Equation of motion - \(III\), We know that,
From the Equation of motion - \(I\), We know that,
Distance travelled \(=\) \(m\)
(Note: Enter your answers with two decimal places)
Time taken \(=\) \(s\)
(Note: Enter your answers with one decimal place)
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