Theory:

I. Calculate the percentage of \(S\) in \(H_2SO_4\).
 
Data:
 
Atomic mass of \(H=1\)
 
Atomic mass of \(S=32\)
 
Atomic mass of \(O=16\)
 
Solution:
 
MolecularmassofH2SO4=2×1+1×32+4×16=2+32+64=98g
 
%ofSinH2SO4=MassofsulphurMolecularmassofH2SO4×100=3298×100=32.65%
 
Therefore, the percentage of \(S\) in \(H_2SO_4=32.65%\)
 
II. Calculate the percentage of \(O\) in \(H_2SO_4\).
 
Data:
 
Atomic mass of \(H=1\)
 
Atomic mass of \(S=32\)
 
Atomic mass of \(O=16\)
 
Solution:
  
MolecularmassofH2SO4=2×1+1×32+4×16=2+32+64=98g
 
%ofOinH2SO4=MassofoxygenMolecularmassofH2SO4×100=1698×100=16.32%
 
Therefore, the percentage of \(O\) in \(H_2SO_4=16.32%\)