Intext solved problem III — task. Science State Board, Class 10.

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The resistance of a wire of length 10 \(m\) is 2

Ω

. If the area of cross section of the wire is

2 \times 10^{- 7} m^{2}

Determine its,

(i) Resistivity

(ii) Conductance, and

(iii) Conductivity.

[Note: Enter the answer up to two decimal places.]

\(L\) \(=\) 10 \(m\)

\(R\) \(=\) 2

Ω

A = 2 \times 10^{- 7} m^{2}

(i) The formula to calculate the resistivity of a material is

\begin{array}{l} ρ = \frac{i i}{i} \\ = \frac{i \times i \times i^{i}}{i} \end{array}

Resistivity, \(\rho\) \(=\)

\times 10^{- 7} Ω m

(ii) The formula to calculate the conductance of a material is

G = \frac{i}{i}

Conductance, \(G\) \(=\) \(mho\)

(iii) The formula to calculate the conductivity of a material is

= \frac{i}{i \times i^{i}}

Conductivity, \(\sigma\) \(=\)

\times 10^{7} mho m^{- 1}

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26. Intext solved problem III