Numerical problems IV — task. Science State Board, Class 10.

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A piece of wire having a resistance \(R\) is cut into five equal parts.
\(\)

(a) How will the resistance of each part of the wire change compared with the original resistance?

If an equal resistance '\(R\)' are connected in series, their equivalent resistance is given as

\begin{array}{l} R_{S} = i i \\ = i i \\ i = \frac{R_{S}}{i} \end{array}

Then, each part of resistance '\(R\)' is equal to times of original resistance.

(b) If the five parts of the wire are placed in parallel, how will the resistance of the combination change?

\begin{array}{l} \frac{1}{R_{P}} = \frac{i}{i} \\ R_{P} = \frac{i}{i} \end{array}

(c) What will be ratio of the effective resistance in series connection to that of the parallel connection?

\begin{array}{l} \frac{R_{S}}{R_{P}} = \frac{(i i)}{(\frac{i}{i})} \\ R_{P} = \frac{i}{i} \end{array}

Thus, the ratio is given as \(:\) .

Did you find an error?

17. Numerical problems IV