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An energy of \(84000\ J\) is required to raise the temperature of \(2\ kg\) of water from \(60\ °C\) to \(70\ °C\). Calculate the specific heat capacity of water.
From the given data,
Temperature of water before energy supply (\(T1\)) \(=\) \(60°\ C\)
Temperature of water ball after energy supply (\(T2\)) \(=\) \(70°\ C\)
Energy Supplied (\(Q\)) \(=\) \(84000\ J\)
Mass (\(m\)) \(=\) \(2\ Kg\)
We know that,
Heat transfer (\(Q\)) is,
Formula to calculate Specific heat capacity is,
Substitute the values,
Specific heat capacity of water \(=\)
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