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At an orbital height of 500 \(km\), find the orbital period of the satellite.
 
Given:
 
\(h\) \(=\) 500 \(km\)
 
\(R\) \(=\) \(6371\ km\)
 
\(v\) \(=\) \(7.616 kms^{-1}\)
 
Formula:
 
T=iπi+iiii+i
 
On substituting the given values, we get
 
T=i×227×i+ii
 
The orbital period of the satellite is  \(minutes\).