23. Five mark exercise problem VIII

Find the equation of a straight line through the intersection of lines \(5x - 6y = 2\), \(3x + 2y = 10\) and perpendicular to the line \(4x - 7y + 13 = 0\).

 

Answer:

 

The equation of the straight line is \(49x - 28y - 156 = 0\)\(49x - 28y + 156 = 0\)\(49x + 28y - 156 = 0\)\(49x + 28y + 156 = 0\).