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In an isosceles \(\triangle ABC\), \(AB = AC\). The base \(BC\) lies on the \(x\)-axis, \(A\) lies on the \(y\)-axis, and x+9y+18=0 is the equation of \(AB\). Find the equation of the straight line along with \(AC\).
 
Answer:
 
The equation of the straight line along \(AC\) is