22. Five mark exercise problem III

 

In the given figure, \(\triangle ABC\) is right-angled at \(C\) and \(DE \perp AB\). Prove that \(\triangle ABC \sim \triangle ADE\) and hence find the lengths of \(AE\) and \(DE\).

 

Answer:

 

(i) In \(\Delta ABC\) and \(\Delta ADE\):

 

 

 

\(\Delta ABC\) similarnot similar \(\Delta ADE\)

 

(ii) The length of \(AE\) is $\frac{i}{i}$ \(cm\).

 

The length of \(DE\) is $\frac{i}{i}$ \(cm\).