Five marks exercise problems IV — task. Mathematics State Board, Class 10.

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1. If the function \(f\) is defined by

f (x) = \{\begin{array}{l} x + 2 \\ 2 \\ x - 1 \end{array} \begin{array}{l} if \\ if \\ if \end{array} \begin{array}{l} x > 1 \\ - 1 \leq x \leq 1 \\ - 3 < x < - 1 \end{array}

; find the values of

(i) \(f(3)\) \(=\)

(ii) \(f(0)\) \(=\)

(iii) \(f(-1.5)\) \(=\)

(iv) \(f(2) + f(-2)\) \(=\)

2. A function \(f: [-5, 9] \rightarrow \mathbb{R}\) is defined as follows:

f (x) = \{\begin{array}{l} 6 x + 1 \\ 5 x^{2} - 1 \\ 3 x - 4 \end{array} \begin{array}{l} if \\ if \\ if \end{array} \begin{array}{l} - 5 \leq x < 2 \\ 2 \leq x < 6 \\ 6 \leq x \leq 9 \end{array}

, Find:

(i) \(f(-3) + f(2)\) \(=\)

(ii) \(f(7) - f(1)\) \(=\)

(iii) \(2f(4) + f(8)\) \(=\)

(iv)

\frac{2 f (- 2) - f (6)}{f (4) + f (- 2)}

\(=\)

\frac{i}{i}

Did you find an error?

10. Five marks exercise problems IV