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A function \(f : [(-3, 7) \rightarrow R\) is defined as follows:
\(f(x) = \begin{cases}
4x^2 - 1 & \text{ if } x= -3 \leq x < 2\\
3x - 2 & \text{ if } x= 2 \leq x \leq 4\\
2x - 3 & \text{ if } x= 4 < x < 7
\end{cases}\)
4x^2 - 1 & \text{ if } x= -3 \leq x < 2\\
3x - 2 & \text{ if } x= 2 \leq x \leq 4\\
2x - 3 & \text{ if } x= 4 < x < 7
\end{cases}\)
Find the following:
\(f(\)−1\()\) \(-\) \(f(\)2\()\) \(=\)
\(\frac{f(2) - f(-1)}{2f(6) - f(0)}\) \(=\)
[Note: Do not reduce the obtained fraction.]
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